R
Rishtaara
Science · Class 12

Current Electricity

Learn Current Electricity with notes, examples, and practice questions.

4 sections15–25 min read6 MCQs · 2 examples

Chapter Overview

Current electricity deals with flow of charge in conductors — drift velocity, Ohm's law, resistance networks, and electrical power.

Core Relations

Current

I = Q/t = nAve_d

Ohm's law

V = IR

Resistance

R = ρL/A

Resistivity

ρ depends on material and temperature

Power

P = VI = I²R = V²/R

Circuits

Series

R_eq = R₁+R₂; same I

Parallel

1/R_eq = 1/R₁+1/R₂; same V

Kirchhoff

ΣI at junction = 0; ΣV in loop = 0

Wheatstone bridge

Balanced when P/Q = R/S

Cells

  • EMF ε: terminal voltage with no current
  • Internal resistance r: V = ε − Ir
  • Cells in series: ε add; parallel: same ε

Solved Examples

Step-by-step solutions — read each step before checking the final answer.

Ohm's law

R=10Ω, V=5V. Find I.

  1. 1I=V/R=0.5A

Answer

0.5 A

Power

100W bulb at 220V.

  1. 1I=P/V≈0.45A
  2. 2R=V²/P≈484Ω

Answer

≈0.45 A, R≈484Ω

Key Points to Remember

  • Conventional current: + to −
  • Potentiometer measures EMF accurately
  • Colour code for resistors

Exam Tips

  • Draw circuit diagram
  • Apply Kirchhoff for complex circuits
  • Check series vs parallel

Formula Cheat Sheet

Quick reference — NCERT board exam formulas

Current & Resistance

  • Current:I = Q/t = nAve_d
  • Ohm's law:V = IR
  • Resistance:R = ρL/A
  • Power:P = VI = I²R = V²/R

Circuits & Cells

  • Series:R_eq = R₁+R₂ ; same I
  • Parallel:1/R_eq = 1/R₁+1/R₂ ; same V
  • Kirchhoff:ΣI at junction = 0 ; ΣV in loop = 0
  • Wheatstone bridge:Balanced when P/Q = R/S
  • Cell:V = ε − Ir

Practice MCQs — Current Electricity

Test your understanding with topic-wise multiple choice questions. Explanations appear after each answer.

Question 1 of 6Score: 0/0

Ohm's law: V =