R
Rishtaara
Mathematics · Class 9

Heron's Formula

Area of triangles using Heron's formula and applications.

3 sections15–25 min read6 MCQs · 2 examples

Chapter Overview

Heron's formula finds the area of a triangle when all three sides are known — without needing height. It uses semi-perimeter s = (a + b + c)/2 and is essential for triangular land and field problems.

Heron's Formula

Semi-perimeter

s = (a + b + c) / 2

Area

Area = √[s(s − a)(s − b)(s − c)]

Applications

  • Use when only three sides are given
  • Works for all types of triangles
  • Combine with unit conversion in word problems
  • Check triangle inequality before applying

Solved Examples

Step-by-step solutions — read each step before checking the final answer.

Example 1: Scalene triangle

Find area of triangle with sides 3 cm, 4 cm, 5 cm.

  1. 1s = (3 + 4 + 5)/2 = 6
  2. 2Area = √[6(6−3)(6−4)(6−5)]
  3. 3= √[6 × 3 × 2 × 1] = √36 = 6

Answer

Area = 6 cm²

Example 2: Equilateral triangle

Side of equilateral triangle is 10 cm. Find area.

  1. 1s = (10 + 10 + 10)/2 = 15
  2. 2Area = √[15 × 5 × 5 × 5]
  3. 3= √1875 ≈ 43.3 cm²

Answer

≈ 43.3 cm²

Key Points to Remember

  • All three sides must be known
  • Units of area are square units
  • 3-4-5 triangle is right-angled with area 6

Exam Tips

  • Calculate s first and show substitution
  • Keep surds exact unless asked to approximate
  • Verify sides satisfy triangle inequality

Practice MCQs — Heron's Formula

Test your understanding with topic-wise multiple choice questions. Explanations appear after each answer.

Question 1 of 6Score: 0/0

Heron's formula needs: